Chemistry, 27.09.2019 01:30 kyusra2008

N2 + 3h2 = 2nh3

for the equation in (2) above, you have 1000. g of n2 and 150.0 g of h2:

a. identify the limiting reactant.

b. calculate the theoretical yield in grams of nh3.

c. calculate the grams of excess reactant.
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Answer from: melissalopez12

The answer to your question is:

a) Hydrogen

b) 850 g of NH3

c) 300 g of N2

Explanation:

N2 + 3H2 ⇒ 2NH3

N2 = 1000 g

H2 = 150 g

a. Identify the limiting reactant.

MW N2 = 28 g

MW H2 = 2 g

MW NH3 = 17g

N2 + 3H2 ⇒ 2NH3

28g 3(2)

1000 g x

x = (1000 x 6)/ 28

x = 214.3 g of H2

Then, the limiting reactant is H2, because is necessary to have 214.3 g of H2 to react with 1000 g of N2, and there are only 150 g.

b. Calculate the theoretical yield in grams of NH3.

N2 + 3H2 ⇒ 2NH3

6g 2(17)g

150g x

x = (150 x 34) / 6

x = 850 g of NH3

c. Calculate the grams of excess reactant.

N2 + 3H2 ⇒ 2NH3

28g 6 g

x 150 g

x = (150 x 28)/ 6

x = 700 g of N2

Excess reactant = 1000g - 700g

= 300 g of N2

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N2 + 3h2 = 2nh3

for the equation in (2) above, you have 1000. g of n2 and 150.0 g of h2:...

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