Question 1 what is the strongest attractive force between a molecule of benzophenone and a molecule of hexane? dipole/dipole interactions london dispersion forces lonic bonding hydrogen bonding dipole/ion interactions

Hydrogen bonding

Explanation:

The molecule of benzophenone (in the picture below) is polar because it has a bond of carbon and oxygen and these elements have huge differences of electronegativity, so they'll have partial charges: oxygen will be with negative partial charge because it has higher electronegativity (it attracts the electrons better).

The molecule of hexane (in the picture below) only has bonds between carbon and hydrogen which have close electronegativity, so the molecule is nonpolar. But, it can form an induced dipole, and the hydrogen will have a partial positive charge for a moment.

When these two molecules approach, the hydrogen and the oxygen must form a bond, which is called hydrogen bonding, and always occurs between hydrogen and an atom with high electronegativity (N, O, and F).

the answer would be b i believe

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied