Chemistry, 02.10.2019 00:30 XxKaitlynnxX

At equilibrium, the concentrations in this system were found to be [n2]=[o2]=0.100 m and [no]=0.400 m. n2(g)+o2(g)↽−−⇀2no(g) if more no is added, bringing its concentration to 0.700 m, what will the final concentration of no be after equilibrium is re‑established?

Answers: 3

Show answers

Answers

Answer from: queenkimm26

The final concentration of NO after equilibrium is re‑established will be:

[NO] = 0.600 M

Explanation:

We know that for a generic reaction aA (g) + bB (g) ⇄ cC (g) + dD (g), where a, b, c, and d are stoichiometric coefficients and A, B, C, and D are reagents and products, the equilibrium constant must be written as:

$K = \frac{[C]^{c}.[D]^{d}}{[A]^{a}.[B]^{b}}$

*brackets [ ], mean molar concentration

Then, as we know the equilibrium concentrations of reagents and products in the reaction $N_{2} (g) + O_{2} (g)$ ⇄ 2 NO (g), the equilibrium constant could be calculated as well:

$K = \frac{[NO]^{2}}{[O_{2}].[N_{2}]}$

$K = \frac{(0.400 M)^{2}}{(0.100 M).(0.100 M)} = 16$

Equilibrium constants only varies with temperature changes. So, K found before could be used with other equilibrium concentrations, supposing no temperature changes.

Let´s analyze what happens if more NO is added:

As more product is added, to re-establish the equilibrium, the reaction will consume NO to form reagents.This will happen in stoichiometric quantities, so supposing 2x the quantity of NO consumed, x amount of nitrogen and x of oxygen will be produced.

$N_{2} (g) + O_{2} (g)$ ⇄ 2 NO (g)

Initial situation: $[N_{2}] = 0.100 M; [O_{2}] = 0.100 M; [NO] = 0.700 M$

Equilibrium situation: $[N_{2}] = 0.100 M + x; [O_{2}] = 0.100 M + x; [NO] = 0.700 M - 2x$

Now, we can re-write equilibrium constan K with this new concentrations:

$K = \frac{[NO]^{2}}{[O_{2}].[N_{2}]} = 16$

$K = \frac{(0.700 M - 2x)^{2}}{(0.100 M + x).(0.100 M + x)} = 16$

Next step is to solve this equation to find x value.

$\frac{(0.700 M - 2x)^{2}}{(0.100 M + x).(0.100 M + x)} = 16$ $\frac{(0.700 M - 2x)^{2}}{(0.100 M + x)^{2}} = 16$

Solving the binomial squares $(a+b)^{2} = a^{2} + 2.a.b + b^{2}$

$\frac{4x^{2}-2.8x+0.49}{x^{2}+0.2x+0.01} = 16$ $4x^{2}-2.8x+0.49 = 16x^{2}+3.2x+0.16$

Grouping terms:

$12x^{2}+6x-0.33 = 0$

The quadratic formula of the roots of the general quadratic equation $ax^{2} +bx+c$ is:

$x_{1} =\frac{-b+\sqrt[]{4.a.c} }{2.a} \\x_{2} =\frac{-b-\sqrt[]{4.a.c} }{2.a}$

Then, for our problem:

$x_{1} =0.050 M\\x_{2} = -0.550 M$

Only one of this answers is correct. To know which one, let´s look wheather equilibrium concentrations are possible or not.

Case $x_{1} =0.050 M$

Equilibrium situation: $[N_{2}] = 0.100 M + x = 0.150 M; [O_{2}] = 0.100 M + x = 0.150 M; [NO] = 0.700 M - 2x = 0.600 M$

As all concentrations are possitive, it´s a possible situation. Let´s analyze the other to confirm.

Case $x_{2} =-0.550 M$

Equilibrium situation: $[N_{2}] = 0.100 M + x = -0.450 M; [O_{2}] = 0.100 M + x = -0.450 M; [NO] = 0.700 M - 2x = 1.800 M$

$x_{2}$ isn´t a possible answer because it results in negative equilibrium concentrations of the reagents. Then Case $x_{1} =0.050 M$ is the correct one.

The answer is: The final concentration of NO after equilibrium is re‑established will be [NO] = 0.600 M

Answer from: Quest

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

Answer from: Quest

Is a logical series of steps

Another question on Chemistry

Chemistry, 22.06.2019 08:00

Identify a strong intermolecular force of attraction between an alcohol

Answers: 1

Answer

Chemistry, 22.06.2019 13:00

Jose and eric were given four samples in lab. the results of their analysis are shown in the table. based on the data they collected, which sample is most likely a metal?

Answers: 1

Answer

Chemistry, 22.06.2019 14:30

Is a pencil falling to the floor anon contact force, a force, or a contact force

Answers: 1

Answer

Chemistry, 22.06.2019 22:30

Which type of intermolecular force is pbr3

Answers: 1

Answer

You know the right answer?

At equilibrium, the concentrations in this system were found to be [n2]=[o2]=0.100 m and [no]=0.400...