Dolomite is a mixed carbonate of calcium and magnesium that decomposes to co2 and the metal oxides mgo and cao upon heating. when 11.15 g of dolomite is heated, 5.70 g of mgo and cao are produced. what is percent by mass of mgco3 in the original sample of dolomite?

The percent by mass of in dolomite is 59.5 %

Explanation:

We are given:

Mass of MgO and CaO produced = 5.70 g

Mass of dolomite = 11.15 g

We know that:

Molar mass of magnesium carbonate = 84.314 g/mol

Molar mass of calcium carbonate = 100.087 g/mol

Molar mass of magnesium oxide = 40.304 g/mol

Molar mass of calcium oxide = 56.077 g/mol

Let the mass of magnesium carbonate in given sample of dolomite be 'x' grams and that of calcium carbonate be '(11.15 - x)' grams

To calculate the number of moles, we use the equation:

Moles of magnesium carbonate = moles

Moles of calcium carbonate = moles

By Stoichiometry of the reaction:

1 mole of magnesium carbonate produces 1 mole of magnesium oxide

So, moles of magnesium carbonate will produce = of magnesium oxide

Mass of magnesium oxide =

Mass of magnesium oxide =

By Stoichiometry of the reaction:

1 mole of calcium carbonate produces 1 mole of calcium oxide

So, moles of calcium carbonate will produce = of calcium oxide

Mass of calcium oxide =

Mass of calcium oxide =

We are given:

Mass of MgO and CaO produced = 5.70 g

To calculate the mass percentage of magnesium carbonate in dolomite, we use the equation:

Mass of dolomite = 11.15 g

Mass of magnesium carbonate = 6.63 g

Putting values in above equation, we get:

Hence, the mass percent of magnesium carbonate in given amount of dolomite is 59.5 %

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