Methane (ch4) effuses through a small opening in the side of a container at the rate of 1.30 × 10 8 mol s 1. an unknown gas effuses through the same opening at the rate of 5.42 × 10 9 mol s 1 when maintained at the same tem- perature and pressure as the methane. determine the molar mass of the unknown gas.

Answer : The molar mass of unknown gas is 92.0 g/mol

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

or,

      ..........(1)

where,

= rate of effusion of methane gas =

= rate of effusion of unknown gas =

= molar mass of methane gas  = 16 g/mole

= molar mass of unknown gas = ?

Now put all the given values in the above formula 1, we get:

Therefore, the molar mass of unknown gas is 92.0 g/mol

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72