Achemist prepares a solution of magnesium bromide by measuring out of into a volumetric flask and filling to the mark with distilled water. calculate the molarity of anions in the chemist's solution. be sure your answer is rounded to the correct number of significant digits.

Check the procedure out.

Explanation:

Hello,

Since neither the mass of magnesium bromide and the volume of the volumetric flask are not given, one can assume arbitrary values and you could modify them whenever you want, thus, let 50.0g of magnesium bromide to be the measured out amount of solute and a 250-mL volumetric flask where the solution is prepared, so the final volume of the solution is 250 mL after the addition of distilled water. In this manner, the bromide anions moles, taking into account there are two bromide moles per magnesium bromide moles, turns out into:

Finally, the required molarity is found:

So, if you have a different measured out amount of magnesium bromide and a different volumetric flask, you just modify the 50.0g and 0.250L for the given values you've eventually got.

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answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.