An analytical chemist is titrating of a solution of cyanic acid with a solution of . the of cyanic acid is . calculate the ph of the acid solution after the chemist has added of the solution to it. note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of solution added.

The pH of the solution is 12.73

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of cyanic acid = 0.8600 M  (Assuming)

Volume of solution = 179.5 mL    (Assuming)

Putting values in equation 1, we get:

Molarity of NaOH = 0.6500 M  (Assuming)

Volume of solution = 274.6 mL    (Assuming)

Putting values in equation 1, we get:

Calculating the remaining moles of NaOH, we get:

Calculating the concentration of NaOH by using equation 1, we get:

Moles of NaOH = 0.02412 moles

Volume of solution = 179.5 + 274.6 = 454.1 mL

Putting values in above equation, we get:

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.

We are given:

Putting values in above equation, we get:

To calculate pH of the solution, we use the equation:

Hence, the pH of the solution is 12.73

where is the following

explanation: