Consider the following equation: sio2 (s) + 3c (graphite) --> sic (s) + 2co (g) δh rxn = 624.6 kj / mol rxn. using the following standard enthalpy of formation data, calculate standard enthalpy of formation for sic (s). a. standard enthalpy of formation sio2 (s) = -910.9 kj/mol b. standard enthalpy of formation co (g) = -110.5 kj/mol

The enthalpy of the formation of is coming out to be -65.3 kJ/mol

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as

The equation used to calculate enthalpy change is of a reaction is:  

For the given chemical reaction:

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

Hence, the enthalpy of the formation of is coming out to be -65.3 kJ/mol.

the answer is b. dilution

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

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