Aluminum bromide reacts with chlorine gas to produce aluminum chloride and liquid bromide,
according to the chemical equation below:
2a1br3 + 3cl2 + 2alcl3 + 3br2
how many moles of aluminum chloride are made if 779 g of chlorine gas are consumed?

779 g of chlorine would produce 7.3 moles of AlCl₃

Explanation:

Given data:

Mass of chlorine gas = 779 g

Number of moles of Aluminium chloride formed = ?

Solution:

Chemical equation:

2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂

Number of moles of chlorine:

Number of moles = mass/ molar mass

Number of moles = 779 g/ 71 g/mol

Number of moles = 11 mol

Now we will compare the moles of chlorine with Aluminium chloride.

                                Cl₂                    :            AlCl₃

                                  3                     :                2

                                  11                     :                 2/3×11 = 7.3 mol

779 g of chlorine would produce 7.3 moles of AlCl₃.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

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