Gas is trapped inside of a cell with volume 140 m3. the gas exerts 7600 pa of pressure against the walls of the cell. a machine then expands the cell and gives off 490 kj of heat to the gas during the process. if the internal energy changed by 140 kj, what is the final volume of the cell? assume the pressure stays constant.
a. 57 m3
b. 94 m3
c. 660 m3
d. 220 m3
e. 190 m3

Option (e) is the correct answer.

Explanation:

The given data is as follows.

          Volume = 140 ,       Pressure = 7600 Pa

         q = 490 kJ,       = 140 kJ

As we know that relation between internal energy and work is as follows.

               140 kJ = 490 kJ + w

                 w = (140 - 490) kJ  

                     = -350 kJ

Now, calculate the final volume using work, pressure and volume change relationship as follows.

         w =

        -350 kJ =

(As, 1 J = )

Which is nearest to 190 .

Thus, we can conclude that the final volume of the cell is 190 .

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.