The oxide of titanium, tio2 is used as a "whitener" in toothpaste. it is obtained from the ore iron (ii) titanate, fetio3.what is the change, if any, in the oxidation number (oxidation state) of titanium in the reaction

There is no change in the oxidation number (oxidation state) of titanium in the reaction

Explanation:

TiO2

⇒ The oxidation number of O = -2

⇒  Since we have O2, this makes 2*-2 = -4

⇒ The oxation number of Ti and O2 together should be 0

   ⇒The oxidation number of Ti is +4

For FeTiO3, it's more complicate because Fe can have several oxidation numbers.

Since FeTiO3 has three  short metal–oxygen bonds in the octahedron  and three  long metal -oxygen bonds.

The valences, obtained from the bond lengths by the bond valence method, is  +2 anapproximately which can be rounded off to oxidation stated +4, respectively for Fe and Ti.

FeTiO3

⇒ The oxidation number of O = -2

  ⇒ We have O3 so this makes 3*-2 = -6

⇒Fe has an oxidation state of +2

⇒The oxidation state of Fe, Ti and O3 together should be 0

⇒Ti has an oxidation state of +4

This means Titanium doesn't change it's oxidation number.

There is no change in the oxidation number (oxidation state) of titanium in the reaction

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: