Calculate the concentration of acetic acid in a buffer solution made from 3.00 ml of 0.50 m acetic acid and 7.00 ml of 0.50 sodium acetate.

Explanation:

The given data is as follows.

      = 0.50 M,   = 3.00 ml

      = 7.00 ml,      

Therefore, calculate the total volume as follows.

             Total volume =

                                    = 3.00 ml + 7.00 ml

                                    = 10.0 ml

Now, calculate the no. of moles of acetic acid as follows.

No. of moles of acetic acid = molarity × volume in mL

                                              = 3.0 × 0.50

                                              = 1.5 mmoles

                                              = moles

(As 1 mole = 0.001 mmol)

Therefore, calculate the concentration of acetic acid as follows.

Concentration of the acetic acid =

                                       =

                                      = 0.15 M

Thus, we can conclude that the concentration of acetic acid in buffer solution is 0.15 M.

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

your parents i think this could be it