Chemistry, 29.11.2019 02:31 Satoetoe24
Asample of impure tin of mass 0.526 g is dissolved in strong acid to give a solution of sn2 . the solution is then titrated with a 0.0448 m solution of no3−, which is reduced to no(g). the equivalence point is reached upon the addition of 3.67×10−2 l of the no3− solution.
find the percent by mass of tin in the original sample, assuming that it contains no other reducing agents.
Answers: 1
= 2.47x10⁻³mol Sn²⁺Another question on Chemistry
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Asample of impure tin of mass 0.526 g is dissolved in strong acid to give a solution of sn2 . the so...
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