15.2 grams of aluminim and 15.2 grams of beryllium both start at room temp 25 degreees, if 46.4 j of heat are added to each seperatley, what are the temp differneces between the two after they have been heated? the specific heat for al equals 0.899 j/g degrees celcuis and be=1.82 j/g degrees celcius

After adding 46.4 J of heat, the final temperature of aluminium is 28.396 ( The temperature  difference is 3.396 °C).

The final temperature of berylium is 26.677 ( the temperature difference is 1.677°C)

Explanation:

Step 1: Data given

Mass of aluminium = 15.2 grams

Mass of berylium = 15.2 grams

Temperature = 25.0°C

46.4 J of heat is added

The specific heat for Al = 0.899 J/g °C

The specific heat for Be=1.82 J/g °C

Step 2: Calculate the final temperature of aluminium

Q = m*c*ΔT

⇒ Q = the heat in Joule = 46.4 J

⇒ m = the mass of Aluminium = 15.2 grams

⇒ c= the specific heat of aluminium = 0.899 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = T2 - 25.0 °C

46.4 J = 15.2g * 0.899 J/g°C * (T2-25.0 °C)

46.4 = 13.6648(T2 - 25.0°C)

46.4 = 13.6648T2 - 341.62

388.02 = 13.6648T2

T2 = 28.396 °C

Step 3: Calculate the final temperature of berylium

Q = m*c*ΔT

⇒ Q = the heat in Joule = 46.4 J

⇒ m = the mass of Aluminium = 15.2 grams

⇒ c= the specific heat of aluminium = 1.82 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = T2 - 25.0 °C

46.4 J = 15.2g * 1.82 J/g°C * (T2-25.0 °C)

46.4 = 27.664(T2 - 25.0)

46.4 = 27.664T2 - 691.6

738 = 27.664T2

T2 = 26.677 °C

After adding 46.4 J of heat, the final temperature of aluminium is 28.396 ( The temperature  difference is 3.396 °C).

The final temperature of berylium is 26.677 ( the temperature difference is 1.677°C)

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