Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid. hcl(aq), as described by the chemical equationmno2(s) + 4hcl(aq) --> mncl2(aq) + 2h2o(l) + cl2(g)how much mno2(s) should be added to excess hcl (aq) to obtain 235 ml of cl2(g) at 25 degrees c and 805 torr?

0.88 g

Explanation:

Using ideal gas equation to calculate the moles of chlorine gas produced as:-

where,

P = pressure of the gas = 805 Torr

V = Volume of the gas = 235 mL = 0.235 L

T = Temperature of the gas =

R = Gas constant =

n = number of moles of chlorine gas = ?

Putting values in above equation, we get:

According to the reaction:-

1 mole of chlorine gas is produced when 1 mole of manganese dioxide undergoes reaction.

So,

0.01017 mole of chlorine gas is produced when 0.01017 mole of manganese dioxide undergoes reaction.

Moles of = 0.01017 moles

Molar mass of = 86.93685 g/mol

So,

Applying values, we get that:-

0.88 g of should be added to excess HCl (aq) to obtain 235 mL of at 25 degrees C and 805 Torr.

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.