Molybdenum (Mo) has a BCC crystal structure, an atomic radius of 0.1363 nm, and an atomic weight of 95.94 g/mol. Compute its density.

The density of the crystal is 10.22 g/cm³

Explanation:

Step 1: Data given

Molybdenum (Mo) has a BCC crystal structure

atomic radius = 0.1363 nm

atomic weight of 95.94 g/mol

Step 2: Calculate density of a bcc crystal

Density ρ= (nA *Mo)/(Vc*Na)

⇒For BCC, n = 2 atoms/unit cell, and realizing that V c  = a ³

a = 4R/√3

Vc =(4R/√3)³

AMo = atomic weight = 95.94 g/mol

ρ = (n*A Mo)/((4R/√3)³ *Na)

⇒with n = 2 atoms/unit cell

⇒ with AMo = 95.94 g/mol

⇒ with Vc =(4R/√3)³  = (4*0.1363*10-7 cm)³ /(√3)³

⇒with Na = 6.022*10^23 atoms/mol

ρ =10.22 g/cm³

The density of the crystal is 10.22 g/cm³