The reaction 2N2O5(g)eys the rate law: rate = k[N2O5]. In which the specific rate constant is 0.00840 s-1. If 2.50 moles of N2O5 were placed in a 5.0-liter container at that temperature, how many moles of N2O5 would remain after 1.00 minute?

1.65 moles of N2O5

Explanation:

The reaction follows a first-order

Rate = K[N2O5] = change in concentration of N2O5/time

Let the concentration of N2O5 after 1 min be y

Initial concentration of N2O5 = number of moles of N2O5/volume of container = 2.5/5 = 0.5 M

Change in concentration = 0.5-y

k = 0.00840 s^-1

t = 1 min = 60 s

0.0084y = 0.5 - y/60

0.5 - y = 0.504y

0.504y+y = 0.5

1.504y = 0.5

y = 0.5/1.504 = 0.33 M

Number of moles = concentration × volume = 0.33×5 = 1.65 moles

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons