Ammonia reacts with oxygen to produce nitrogen monoxide and water. what volume of nitrogen monoxide will result a complete reaction with 2800 l of oxygen at stp?

2240L of NO will be produced

Explanation:

First, we need to write a balanced equation for the reaction.

4NH3 + 5O2 —> 4NO + 6H2O

From the equation, it is evident that

5L of O2 produced 4L of NO.

Therefore, 2800L of O2 will produce xL of NO. i.e

xL of NO = (2800x4)/5 = 2240L

Therefore, 2800L of O2 will produce 2240L of NO