Please hurry!! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting reactant?

The answer to your question is Al₂O₃

Explanation:

Data

mass of Al₂O₃ = 3.87 g

mass of H₂O = 5.67 g

Balanced chemical reaction

                Al₂O₃  +  H₂O   ⇒   2Al(OH)₃

- Calculate the molar mass

Al₂O₃ = (27 x 2) + (16 x 3) = 102 g

H₂O = (1 x 2) + 16 = 18

- Calculate the theoretical and experimental proportion

Theoretical proportion = 102/ 18 = 4.67

Experimental proportion = 3.87/5.67 = 0.68

- Conclusion

As the experimental proportion diminishes, we conclude that the limiting reactant is Al₂O₃.

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explanation:

the dependant variable is spilled water

the independent is the heat