Boyle’s, Charles, Gay-Lussac’s problems. How to set up and solve.

Explanation:

Boyle's Law:

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula when Final temperature is to be calculated,

P₁V₁ = P₂V₂

1.8 atm × 350 L = 1 atm × V₂

V₂ = 630 atm. L/1 atm

V₂ = 630 L

Charles Law:

"The volume of given amount of gas is directly proportional to its  temperature by keeping the pressure and number of moles constant"

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

If the three values are given the forth one can be calculated.

For example,

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 4.5 L × 348 K / 298 k

V₂ = 1566 L.K / 298 K

V₂ = 5.3 L

Gay-Lussac's Law:

"The pressure of given amount of gas is directly proportional to its  temperature by keeping the volume and number of moles constant"

Mathematical expression:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂ = Final temperature

If the three values are given the forth one can be calculated.

For example,

P₁/T₁ = P₂/T₂

P₂ = P₁T₂/T₁  

P₂ = 4.5 atm × 348 K / 298 k

P₂ = 1566 atm.K / 298 K

P₂ = 5.3 atm

6.4 cm (max) - 25 cm (min)

1 is the answer to this problem