A 125g bar of aluminum at 22 degrees celsius. determine the final temperature of the aluminum, if the amount of energy applied is equal to 3600 calories. the specific heat of aluminum is .90 j/gc

Answer : The final temperature of the aluminum is,

Explanation :

Formula used :

where,

q = heat = 3600 cal = 15062.4 J    (1 cal = 4.184 J)

m = mass of aluminum = 125 g

c = specific heat of aluminum =

= final temperature = ?

= initial temperature =

Now put all the given values in the above formula, we get:

Thus, the final temperature of the aluminum is,

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explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :