Calculate the value of K p for the equation C ( s ) + CO 2 ( g ) − ⇀ ↽ − 2 CO ( g ) K p = ? given that at a certain temperature C ( s ) + 2 H 2 O ( g ) − ⇀ ↽ − CO 2 ( g ) + 2 H 2 ( g ) K p 1 = 3.23 H 2 ( g ) + CO 2 ( g ) − ⇀ ↽ − H 2 O ( g ) + CO ( g ) K p 2 = 0.693

kp  = 1.55

Explanation:

To get to this reaction, we just need to sum the other two reactions, and multiply coefficients if it's needed so:

C(s) + 2H₂O(g) ⇄CO₂(g) + 2H₂(g)   Kp1 = 3.23    (1)

H₂(g) + CO₂(g) ⇄ H₂O(g) + CO(g)    Kp2 = 0.601   (2)

we will multiply eqn 2 by 2 because we need to eliminate H₂

2H2(g) + 2CO2(g) ⇄ 2H2O(g) + 2CO(g)    Kp = (0.601)²

Now, add both equation

C(s) + 2H₂O(g) ⇄CO₂(g) + 2H₂(g)   Kp1 = 3.23  

2H2(g) + 2CO2(g) ⇄ 2H2O(g) + 2CO(g)    Kp = (0.601)²

we have,

C(s) + CO₂(g) ⇄ 2CO(g)  

Now the value of Kp will be:

kp = 3.23 × (0.693)²

kp  = 1.55

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