A compound of molar mass 161 g/mol contains only carbon, hydrogen, bromine, and oxygen. Analysis reveals that the compound contains 12 times as much carbon as hydrogen by mass. Find the molecular formula. Express your answer as a chemical formula.

Explanation:

It is known that,

       Molar mass of Br = 80 g/mol

       Molar mass of O = 16 g/mol

       Molar mass of H = 1.09 g/mol

      Molar mass of C = 12 g/mol

Now, total mass of the compound is calculated as follows.

          = 161

             13x + 16 m + 80 = 161

We assume that m = 1. Hence, the value of x will be as follows.

            x =

               = 5

As per the formula 12x = 12y

or,        x = y = 5

Therefore, molecular formula of the given compound is .

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml