The volume of an ideal gas has decreased from 6.400 L to 20.00 mL at a constant pressure of 3.450 atm. Determine the value of work for this process.

Work = 22.011  j

Explanation:

Given data:

Initial volume = 6.4 L

Final volume = 20.00 mL

Constant pressure = 3.45 atm

Work = ?

Solution:

First of all we will convert the mL into L.

Final volume = 20.00 mL × 1 L/1000 mL

Final volume = 0.02 L

Formula:

Work = Pressure × ΔV

ΔV = initial volume - final volume

ΔV = 6.4 L - 0.02 L

ΔV = 6.38 L

Now we will determine the work done.

Work = Pressure × ΔV

Work = 3.450 atm  × 6.38 L

Work = 22.011 atm.L

Work = 22.011  j

describe matter a earth

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole