Morphine has the formula C17H19NO3. It is a base and accepts one proton per molecule. It is isolated from opium. A 0.682g sample of opium is found to require 8.92 mL of a 0.0116 M solution of sulfuric acid for neutralization. Assuming that morphine is the only base present in opium, calculate the mass (in grams) of morphine in the sample of opium.
Reaction equation: 2 C17H19NO3 + H2SO4 --> Product

The mass of morphine is 0.059 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of sulfuric acid solution = 0.0116 M

Volume of solution = 8.92 mL

Putting values in above equation, we get:

The given chemical equation follows:

By Stoichiometry of the reaction:

1 moles of sulfuric acid reacts with 2 moles of morphine

So, of sulfuric acid will react with =

To calculate the mass of morphine for given number of moles, we use the equation:

Molar mass of morphine = 285.34 g/mol

Moles of morphine =

Putting values in above equation, we get:

Hence, the mass of morphine is 0.059 grams