A major component of gasoline is octane C8H18. When liquid octane is burned in air it reacts with oxygen O2 gas to produce carbon dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of 0.085mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.

The number of mole of carbon dioxide (CO₂) produced by the reaction of 0.085 mole of oxygen (O₂) is 0.1 mole

We'll begin by writing the balanced equation for the reaction. This is given below:

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

From the balanced equation above,

25 moles of O₂ reacted to produce 16 moles of CO₂.

With the above information, we can obtain the number of mole of CO₂ produced by the reaction of 0.085 mole of O₂. This can be obtained as follow:

From the balanced equation above,

25 moles of O₂ reacted to produce 16 moles of CO₂.

Therefore,

0.085 mole of O₂ will react to produce = = 0.1 mole of CO₂.

Thus, the number of mole of CO₂ produced from the reaction is 0.1 mole

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0.054 moles of carbon dioxide will be produced

Explanation:

Step 1: Data given

Number of moles oxygen = 0.085 moles

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of carbon dioxide

For 2 moles octane we need 25 moles oxygen gas to produce 16 moles carbon dioxide gas and 18 moles water vapor

0.0544

For 0.085 moles O2 we'll have 16/25 * 0.085 = 0.054 moles CO2

0.054 moles of carbon dioxide will be produced

answer: c.

explanation: