How many grams of NH3 are required to produce 4.65 g of HF

1.32g

Explanation:

Given parameters:

Mass of HF   = 4.65g

Unknown:

Mass of NH₃ = ?

Solution:

We need to know the reaction equation first of all. The reaction that will produce HF involves;

                 2NH₃    +    5F₂    →    N₂F₄   + 6HF

Now that we know the reaction equation;

Find the number of moles of the HF;

        Number of moles  =

         Molar mass of HF  = 1 + 19 = 20g/mol

        Number of moles  =   = 0.23mole

From the balanced reaction equation;

        6 moles of HF is produced from 2 moles of NH₃  

        0.23 moles of HF will be produced from      = 0.08moles

Now we find the mass of NH₃

          Mass of NH₃ = number of moles x molar mass

                   Molar mass of NH₃  = 14 + 3(1) = 17g/mol

         Mass of NH₃   = 0.08 x 17  = 1.32g

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.