Based on the equation below, how many moles of aluminum sulfate (Al2(SO4)3) will be produced from the reaction of 5.8 moles of aluminum hydroxide (Al(OH)3) and excess sulfuric acid (H2SO4)?
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
A. 2.9 moles of aluminum sulfate
B. 3.9moles of aluminum sulfate
C. 5.8 moles of aluminum sulfate
D. 11.6 moles of aluminum sulfate
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Based on the equation below, how many moles of aluminum sulfate (Al2(SO4)3) will be produced from th...
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