2PbS(s) + 3O2(g)  2PbO(s) + 2SO2(g) H = -827.4 kJ What is the volume of sulfur dioxide produced at STP if 975 kJ of heat are liberated?

Explanation:

Hello,

In this case, given the reaction:

827.4 kJ of heat are releasing 2 moles of sulfur dioxide, thus, for 975 kJ we find the following released moles:

Then, at STP conditions (273K and 1atm) we compure the volume by using the ideal gas equation:

Regards.