How many moles of a gas sample are in a 20.0 L container at 373 K and 203 kPa? The gas constant is 8.31 L−kPa/mol−K. A)0.33 mole B)0.65 mole C)1.30 moles D)3.05 moles

Option (C) 1.30 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 20L

Temperature (T) = 373K

Pressure (P) = 203 kPa

Gas constant (R) = 8.31 L.kPa/mol.K.

Number of mole (n) =...?

The number of mole of the gas in the container can obtained by applying the ideal gas equation as illustrated below:

PV = nRT

Divide both side by RT

n = PV /RT

n = 203 x 20 / 8.31 x 373

n = 1.30 mole.

Therefore, 1.30 mole of the gas is present in the container.

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