What is the mean rate of reaction 3.4g of copper sulphate was produced in 3 days? please help me

8.1×10^-8 mols-1

Explanation:

Now we have the mass of copper sulphate produced after three days. Recall that the rate of reaction is given as;

Rate= change in the concentration of product/time

At the beginning of the reaction, there was 0 moles of copper sulphate

After 72 hours or 259200 seconds, there was 3.4g/160gmol-1 = 0.021 moles of copper sulphate.

Note that 160gmol-1 is the molar mass of copper sulphate.

Hence;

Rate of reaction= 0.021 moles /259200 seconds

Hence, the rate of reaction is 8.1×10^-8 mols-1

Rate of reaction= 8.1×10^-8 mols-1

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