A ground state hydrogen atom absorbs a photon of light having a wavelength of 92.57 nm. It then gives off a photon having a wavelength of 954.3 nm. What is the final state of the hydrogen atom? Values for physical constants can be found in g

the final state of the hydrogen atom = 3

Explanation:

From the given information;

Let first calculate the amount of energy by the ground state atom during the atoms absorbs  photon light  by using the formula:

where;

h = planck's constant =

c = speed of light =

λ = wavelength = 92.57 nm = 92.57 × 10⁻⁹ m

The energy emitted by the hydrogen atom is calculated by using the same formula from above ; but here , the wavelength λ = 954.3 nm = 954.3 × 10⁻⁹ m

The change in the energy absorbed is:

The final state of the atom can be determined by using the relation:

where;

= Rydberg constant = 2.18 × 10⁻¹⁸ J

Thus; the final state of the hydrogen atom = 3

1.solid

2.carbon dioxide

3.helium

the answer is 75.0%.