If 0.360 J of heat is added to 0.7402 g of water, how much will the temperature increase?

ΔT = 0.116 °C

Explanation:

Using Formula

Q = mc ΔT

Where Q = 0.360, c = 4.184 and m = 0.7402

ΔT = Q/mc

ΔT = 0.360/ (4.184)(0.7402)

ΔT = 0.360 / 3.097

ΔT = 0.116 °C

So, The change in Temperature/Increase in Temperature is 0.116 °C

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