Thulium-167 has a half-life of 9.25 days. If you begin with 48 grams of thulium-167, how much of the original isotope will remain after 37 days?

2.3125g

Explanation:

Half-life referred to the time required for a quantity to reduce to half of its initial value, It used to calculate how unstable atoms undergo, or the period of time and atom can survive, radioactive decay.

Given:

t(1/2)= 9.25days

Initial mass of Thulium-167 = 48grams

We need to calculate the remaining amount after 37days.

Since we know that 1 half life = 9.25 days

Then 37 days means ( 37/9.25) half lives

37days means 4 half life

That means the 38grams of Thulium-167 will be halved by 4 times.

Then the ratio between the initial Amount and the amount remaining after 37 days can be calculated as. 0.5^(4)

= 37days × 0.5^(4)

= 2.3125g

the remaining amount of Thallium-167 after 37days is 2.3125g