What is the molarity of a 50.0ml aqueous solution containing 10.0 grams of hydrogen peroxide H2O2

Molarity= No of moles of solute * 1000 / vol solution in ml

No of moles= Given mass / Molar mass

Given Mass of solute (H2O2)= 10g

Molar mass of H2O2=34gmol^-1

No of moles= 10/34= 0.294 moles

Volume of solution=50ml

Molarity =   0.294*1000 / 50

Molarity = 5.8M

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml