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.![\Delta G^o=\Delta H^o-T\Delta S^o\\\\\Delta G^o=-631-[298\times (-0.430)]\ kJ\\ \\\Delta G^o=-631-(-128.14)\ kJ\\\\\Delta G^o=-502.86\ kJ](/tpl/images/0770/6490/cfc98.png)
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For the reaction 3C2H2(g)---> C6H6(l) at 25 C the standard enthalpy change is -631 kj and the sta...
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