50.00 mL of a solution containing 0.15 M CH2 (CO2 H)2 and 0.020 M MnSO4 1. Calculate the mass in g of malonic acid required.

Watch your sig figs! (enter just the number)

Explanation:

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In this case, for the given volume and molarity of malonic acid (solute), we can compute the mass by first computing the moles considering the definition of molarity:

Then, since the molar mass of the malonic acid is 104.1 g/mol, we can compute the required mass in g of malonic acid for the preparation of that solution as shown below:

Notice that the shortest number is the molarity (0.15 M) with two significant figures, that is why the answer is displayed with two significant figures too.

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d.) circle motion requires a force to give it a centripetal acceleration.

am i too late?

explanation: