What volume of hydrogen is formed when 3.00 g of magnesium react with an excess of dilute sulfuric acid is
carried out under room temperature and pressure at 1 atm.

Volume of hydrogen gas formed = 3.1 L

Explanation:

Given data:

Mass of magnesium = 3.00 g

Temperature = room = 27°C (27+273 = 300 K)

Pressure = 1 atm

Volume of hydrogen gas formed = ?

Solution:

Chemical equation:

Mg + H₂SO₄    →       MgSO₄ + H₂

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 3.00 g/ 24 g/mol

Number of moles = 0.125 mol

Now we will compare the moles Mg with hydrogen.

                    Mg             :             H₂

                     1                :              1

                   0.125          :          0.125

Volume of hydrogen:

PV = nRT

1 atm × V = 0.125 mol  ×  0.0821 atm.L /K.mol × 300 k

V = 3.1atm.L/1 atm

V = 3.1 L

може ли да зареждате повече информация, моля

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.