Be sure to answer all parts. Show the overall reaction for formation of racemic 3−bromohexane from (E)−3−hexene by entering the structures of the products and reactants in the template provided. Part 1 out of 3 draw structure ... arr draw structure ... + draw structure ... (E)−3−hexene (S)−3−bromohexane (R)−3−bromohexane Racemic product = 50% (S) and 50% (R)

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Explanation:

The mechanism for the formation of bromohexane from hexene has been clearly shown in the image attached to this answer.

Hexene is attacked by HBr and a carbocation is first formed as shown. The carbocation is flat and planar. it can be attacked on either face by the bromide ion.

Attack on either faces yields a racemic mixture of the R and S enantiomer as shown in the image.

You can use the mechanism shown to fill in the structures.

am i too late?

explanation:

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.