Calculate the number of moles of Na+ ions in 25g of sodium carbonate?

Explanation:

First, we need to calculate the number of moles of sodium carbonate we have in a 25 g sample. To calculate this, we will

find the molar mass of sodium carbonate (Na2CO3):

⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen

⇒ 2 × 23 + 12 + 3 × 16

⇒ 46 + 12 + 48

⇒ 106g/mol

Thus, the molar mass of Na2CO3 is 106g/mol.

Therefore, number of moles = 25 ÷ 106

=> 0.2358 mol

Now, we know that every mole of Na2CO3 have 0.2358 moles of Na+ ions. Hence, total moles of Na2CO3 is 0.4716 moles

Number of ions present = 6.022 × 1023 × 0.4716 mol = 2.84 × 1023ions

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

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