Chemistry, 16.12.2020 16:10 heintzelmanvp6ir6d
Sulfur dioxide gas reacts with oxygen to form sulfur trioxide gas, as represented by the equation2 SO2(g) + O2(g) <>2 SO3(g) ∆H = −197.8 kJ In order to obtain the equilibrium system above, 2.60 mol of SO2(g) and 2.30 mol of O2(g) are injected into a 1.00 L container. When the system reaches equilibrium, the concentration of the remaining SO2(g) is 1.32 mol/L. The concentration of O2(g) at equilibrium is mol/L. (do NOT write units, simply give a 3-digit numeric answer
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Sulfur dioxide gas reacts with oxygen to form sulfur trioxide gas, as represented by the equation2 S...
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