What is the percent composition of Ca(C2H3O2)2? Select one:
a) 25.3% Ca, 30.4% C, 3.8% H, 40.5% O
b) 40.4% Ca, 24.2% C, 3.1% H, 32.3% O
c) 6.67% Ca, 26.67% C, 40.0% H, 26.67% O
d) 12.5% Ca, 25% C, 37.5% H, 25% O

A

Explanation:

RMM of ca(c2h302)2=158

%Ca= 40/158×100=25.3

%C=48/158×100=30.3

%H=6/158×100=3.7

%O=64/158×100=40.5

a) 25.3% Ca, 30.4% C, 3.8% H, 40.5% O

Explanation:

Molar mass of Ca(C₂H₃O₂)₂  = 158.160 g/mol

percent composition:

Ca = (40 /158.160 ) × 100

Ca = 25.3%

C = (48 /158.160 ) × 100

C = 30.4%

H = (6 /158.160 ) × 100

H = 3.8%

O = (64 /158.160 ) × 100

O = 40.5%

40.5% + 3.8% + 30.4% + 25.3% = 100%

It means 1st option is correct.

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

possibly, yes.

explanation:

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