What temperature change in °C is produced when 4430 Joules are absorbed by 237 grams of water?

4.46 °C

Explanation:

Step 1: Given and required data

Step 2: Calculate the temperature change

We will use the following expression.

Q = c × m × ΔT

ΔT = Q / c × m

ΔT = 4430 J / (4.186 J/g.°C) × 237 g

ΔT = 4.46 °C

The temperature change is 4.46 °C.

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a

4d^55s^1 ( third choice)