Chemistry, 14.01.2021 16:10 hjamileth77

Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O. Determine its empirical formula.

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Answer from: alexabdercmur

Considering the definition of empirical formula, the empirical formula is H₂N₁O₂= H₂NO₂

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers small as possible.

Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O.

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 29.17 grams of N, 4.20 grams of H and 66.63 grams of O.

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

N: $\frac{29.17 grams}{14 \frac{grams}{mole} }$ = 2.08 molesH: $\frac{4.20 grams}{1 \frac{grams}{mole} }$ = 4.20 molesO: $\frac{66.63 grams}{16 \frac{grams}{mole} }$ = 4.16 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

N: $\frac{2.08 moles}{2.08 moles}$ = 1H: $\frac{4.20 moles}{2.08 moles}$ = 2.02 ≅ 2O: $\frac{4.16 moles}{2.08 moles}$ = 2

Therefore the H: N: O mole ratio is 2: 1: 2

Finally, the empirical formula is H₂N₁O₂= H₂NO₂

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Answer from: davidzalinski1051

the empirical formula is H_2NO_2

Explanation:

The empirical formula is

The following information is given

It contains 29.17 mass percentage of N

4.20 mass percentage of H

And, 66.63 mass percentage of 0

Now based on the above information, the empirical formula is H_2NO_2

hence, the same is to be considered and relevant too

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Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass % O. Determine its empi...