What volume of 0.130 M HCl is required for the complete neutralization of 1.30 g of NaHCO3 (sodium bicarbonate)?

Volume required is 0.115 L or 115 ml

Explanation:

moles of =

The balanced chemical equation is:

1 mole of requires = 1 mole of HCl

Thus 0.015 mol of requires = mole of HCl

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in L

Thus volume required is 0.115 l or 115 ml

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