Show your calculations for full marks
1. Calculate the mass of CaCO3(s) required to react with 25.0 mL of 0.75M HCl(aq).
CaCO3(s) + 2 HCl(aq) → CaCl2(aq) + CO2(g) + H2O(1)

0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 0.75 M

Volume of solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

According to stoichiometry :

2 moles of require = 1 mole of

Thus 0.01875 moles of will require=  of

Mass of

Thus 0.9375 g of is required to react with 25.0 ml of 0.75 M HCl

the millers tale is the answer.

space exploration has led to the development and technological improvement of many everyday items. (if this answer is wrong i will find the right answer) : )