Calculate the quantitative concentration of HCl in the solution if in the reaction of 500 cm3 the solution with AgNO3 produces 0.7 g of AgCl AgNO3 + HCl > AgCl + HNO3

9.77x10⁻³M HCl

Explanation:

Assuming the solution of AgNO₃ is in excess:

Based on the chemical equation:

AgNO₃ + HCl → AgCl + HNO₃

We must find the moles of AgCl that will be produced. With the moles and knowing 1 mole of AgCl is produced from 1 mole of HCl we can find the moles of HCl and its concentration as follows:

Moles AgCl -Molar mass: 143.32g/mol-:

0.7g AgCl * (1mol / 143.32g) = 4.88x10⁻³moles AgCl = Moles HCl

As the volume of the solution is 500cm³ = 0.500L, the concentration of HCl is:

4.88x10⁻³moles HCl / 0.500L =

the answer is a. co2, this would be colder than the : )

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :