You now know that [Pb+2] = 0.17 M. Calculate [Cl-].

0.34 M

Explanation:

I assume that the compound is PbCl2.

One mole of PbCl2 contains one mol of Pb+2 and 2 moles of Cl-

Molarity (M)= moles (n) /Volume (V)

Moles Pb2+ = M x V = 0.17 V

Moles Cl- = moles Pb2+ x (2 moles Cl-/1 mole Pb2+) = 0.17 V x 2 = 0.34 V

M Cl- = moles Cl-/V = 0.34V/V = 0.34 M

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)