Consider the chemical equations shown here. C(s) + 2H2(g) → CH4(g) C(s) + 2Cl2(g) → CCl4(g) H2(g) + Cl2(g) → 2HCl(g) What is the overall equation for the reaction that produces CCl4 and HCl from CH4 and Cl2? Upper C upper H subscript 4 (g) plus upper C l subscript 2 (g) right arrow upper C upper C l subscript 4 (g) plus upper H upper C l (g). Upper C upper H subscript 4 (g) plus 4 upper C l subscript 2 (g) right arrow upper C upper C l subscript 4 (g) plus 4 upper H upper C l (g). Upper C upper H subscript 4 (g) plus upper C l subscript 2 (g) plus upper H 2 (g) right arrow upper C upper C l subscript 4 (g) plus upper H upper C l (g).

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.