Chemistry, 30.03.2021 01:00 sirdre1982
3BaCl2 + 2Na3P → Ba3P2 + 6NaCl
185 grams of barium chloride react with 55.5 grams of sodium phosphide.
a) What is the limiting reactant?
b) How many grams of Ba3P2 would be produced?
c) How many grams of the excess reactant are left over?
Answers: 2
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3BaCl2 + 2Na3P → Ba3P2 + 6NaCl
185 grams of barium chloride react with 55.5 grams of sodium phosphi...
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